1. Register NOW and become part of this fantastic knowledge base forum! This message will go away once you have registered.

Calculating degree of phase shift bewteen 2 sine waves!!

Discussion in 'Recording' started by aarongammon, Jan 29, 2004.

  1. aarongammon

    aarongammon Guest

    Hi everyone, Im new here (so hopefully Im posting this in the right place/want to apologise in advance if Im not...)
    I want to calculate the degree of phase shift between two sine waves of the same frequency. I have the following formula (but cant find the right symbols on my keyboard (!)):

    degree of phase = time difference * frequency * 360

    If time difference * frequency > 1, my answer = > 360. Should I omit whole numbers before multiplying by 360...?
    (Im studying a degree in Recording Arts at the moment, and am aware of the implications of phase differences etc, so am sure the question is relevant to this sort of forum (!) (honest!!)

    Many thanks. Aaron
     
  2. aarongammon

    aarongammon Guest

    Think Ive figured it out!
    (Bare with me...)

    time difference * frequency = time difference / period

    It makes sense to me to omit whole numbers after dividing the time difference by the period (to get the fraction of the cycle left), then multiply by 360 to get the degree of phase shift!!!

    Does anyone think this is wrong?
    Thanks again. Aaron
     
  3. Steve Halko

    Steve Halko Guest

    Yes, you can either:

    1. take just the fractional part of time diff/period, then multiply by 360, or

    2. (time diff * freq * 360) modulo 360

    Either way gives you the same answer.
     
  4. aarongammon

    aarongammon Guest

    Great!
    Thanks for your help Steve
     

Share This Page